All categories

3 years ago

Which of the following is the equation of a line parallel to the line y = 4x + 1,

Mathematics

1 answer:

Lisa [10]3 years ago

4 0

Answer:

y = 4x - 19

Step-by-step explanation:

The line is parallel to the line whose equation is;

y = 4x + 1

Parallel lines have the same slope so the slope of our line is 4.

The line passes through point (5,1)

Slope = change in y ÷ change in x

Taking another point (x,y) on the line,

Slope = $\frac{y-1}{x-5}$ = 4

y - 1 = 4x - 20

y = 4x - 19

You might be interested in

A car travels 20 mph slower in a bad rain storm than in sunny weather. the car travels the same distance in 2 hrs in sunny weath

ycow [4]

You can create two equations.

"A car travels 20 mph slower in a bad rain storm than in sunny weather."

$\sf x-20=y$

Where 'x' represents speed in sunny weather and 'y' represents speed in rainy weather.

"The car travels the same distance in 2 hrs in sunny weather as it does in 3 hrs in rainy weather."

$\sf 2x=3y$

Where 'x' represents speed in sunny weather and 'y' represents speed in rainy weather.

We want to find the speed of the car in sunny weather, or 'x'. Plug in the value for 'y' in the first equation into the second equation.

$\sf \boxed{\sf x-20}=y$
$\sf 2x=3y\rightarrow2x=3(x-20)$

Distribute:

$\sf 2x=3x-60$

Subtract 3x to both sides:

$\sf -x=-60$

Divide -1 to both sides:

$\sf x=60$

So the car goes 60 mph in sunny weather.

5 0

2 years ago

In which set(s) of numbers would you find the number 0?

Harlamova29_29 [7]

Apparently it’s all of them

3 0

2 years ago

Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.

vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

$\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152$

To find the area of the circumscribed circle:

$r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95$

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

$AC=\sqrt{10.152^2-8^2}\approx 6.25$

The area of the triangle is:

$A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25$

The semiperimeter of the triangle is:

$\dfrac{10.152+6.25+8}{2}\approx 24.4$

The radius of the circle is therefore $\dfrac{25}{24.4}\approx 1.025$

The area of the inscribed circle then is $\pi\cdot (1.025)^2\approx 3.298$ .

Hope this helps!

6 0

3 years ago

Answer this question Angie and her friends are 3/4 of a pizza.Her brother joe ate 2/3 of what was left.How much did joe eat?

Alja [10]

If Angie and her friends ate 3/4 of a pizza, that means that 1/4 is left.
Joe ate 2/3 of 1/4 of a pizza. To find out how much he ate, multiply 1/4 by 2/3.

$\frac{1}{4}* \frac{2}{3}= \frac{2}{12}$ because you multiply fractions straight across.

Your answer is 2/12 or 1/6 of the pizza

4 0

2 years ago

Read 2 more answers

If PQR is a triangle,given that /PQ\=15m, /QR\=17m and /RP\=18m.Find the area of the triangle to the nearest whole number.

nydimaria [60]

Answer:

118.3 m²

Step-by-step explanation:

Step 1. Calculate the semiperimeter (s).

s = (p + q + r)/2

s = (17 + 18+ 15)/2

s = 50/2