Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
X=200
2/3 of 15 is 10 make that negative add it to the other side 1/5x = 40 and then multiply 40 by 5 to get your answer
Check
1/5 of 200 is 40 - 10 = 30
40-10=30
30=30
Answer:
90 liters
Step-by-step explanation:
please mark me as brainlest
Answer:
A.2sinxcosx
Step-by-step explanation:
We know the trig identity
Sin (2a) = 2 sin a cos a
sin (2x) = 2 sin x cos x