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sergey [27]
4 years ago
13

Which of the following is the equation of a line parallel to the line y = 4x + 1,

Mathematics
1 answer:
Lisa [10]4 years ago
4 0

Answer:

y = 4x - 19

Step-by-step explanation:

The line is parallel to the line whose equation is;

y = 4x + 1

Parallel lines have the same slope so the slope of our line is 4.

The line passes through point (5,1)

Slope = change in y ÷ change in x

Taking another point (x,y) on the line,

Slope = \frac{y-1}{x-5} = 4

y - 1 = 4x - 20

y = 4x - 19

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jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

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Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

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3 years ago
What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?
Maksim231197 [3]
X=200
2/3 of 15 is 10 make that negative add it to the other side 1/5x = 40 and then multiply 40 by 5 to get your answer
Check 
1/5 of 200 is 40 - 10 = 30
40-10=30
30=30
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