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larisa [96]
3 years ago
7

How does the graph of g(x) = (x - 3)^3 + 4 compare to the parent function f(x)=x^3 ?​

Mathematics
2 answers:
masha68 [24]3 years ago
7 0

Answer:

f(x) has moved:

4 units in the positive y direction i.e upwards

3 units in the positive x direction

Step-by-step explanation:

to get g(x), f(x) has undergone the following transformations

f(x) = x³

f1(x) = x³ + 4      (translation of 4 units in the positive y direction i.e upwards)

f2(x) = g(x)  = (x-3)³ + 4 (translation of 3 units in the positive x direction i.e towards the right)

Kipish [7]3 years ago
4 0

Answer:

The modified function has a translation of 3 units to the right and 4 units up compared to the parent function.

Step-by-step explanation:

Let's change both functions to y.

How does y = (x - 3)^3 + 4 compare with the parent function y = x^3?

Start with y = (x - 3)^3 + 4 and subtract 4 from both sides.

y - 4= (x - 3)^3

Now compare the function above with the parent function below.

y = x^3

We notice two differences. y of the parent function becomes y - 4 in the modified function. x of the parent function becomes x - 3 in the modified function.

When you replace x by x - h, the function is translated h units horizontally. The translation is to the right if h is positive and to the left if h is negative.

When you replace y by y - k, the function is translated k units vertically. The translation is up if k is positive and down if k is negative.

In the modified function, x became x - 3.

Compare x - 3 with x - h.

h = 3

3 is positive, so the modified function was translated 3 units to the right.

In the modified function, y becomes y - 4.

Compare y - 4 with y - k.

k = 4

4 is positive, so the modified function is translated 4 units up.

Answer:

The modified function has a translation of 3 units to the right and 4 units up compared to the parent function.

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egoroff_w [7]

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Step-by-step explanation:

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How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
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