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Alenkasestr [34]

3 years ago

12

Data represented by quantities is called ______ data. A. categorical B. numerical

2 answers:

solong [7]3 years ago

6 0

It’s b, numerical so yeah hope this help

FrozenT [24]3 years ago

3 0

It is b it is numerical

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Solve for x: x5 + x4 − 7x3 − 7x2 − 144x − 144 = 0

motikmotik

$x^5 + x^4 - 7x^3 - 7x^2 -144x - 144 = 0 \\x^4(x+1)-7x^2(x+1)-144(x+1)=0\\(x^4-7x^2-144)(x+1)=0\\\\x+1=0\Rightarrow x=-1\\\\x^4-7x^2-144=0\\x^4-16x^2+9x^2-144=0\\x^2(x^2-16)+9(x^2-16)=0\\(x^2+9)(x^2-16)=0\\(x^2+9)(x-4)(x+4)=0\\\\x^2+9=0\vee x-4=0 \vee x+4=0\\x=4 \vee x=-4\\\\x\in\{-4,-1,4\}$

6 0

3 years ago

Read 2 more answers

Work the following pricing problems for services rendered. (For all calculations use hundredths.)

Lesechka [4]

Answer:

Hourly Rate = $12.22 per hour

Step-by-step explanation:

$\text{Labor Time = }4\tfrac{1}{2}=4.5\thinspace{ hours}$

Overhead Rate = 95%

Retail price of parts = $134.75

Total cost of job = $241.98

Cost of labor = Total cost - Retail price

= 241.98 - 134.75

= $107.23

Now, labor works for 4.5 hours and ears a total amount of $107.23

$\implies\text{Amount earned in one hour or hourly rate = }\frac{107.23}{4.5}\\\\\implies \text{Hourly rate = }\$23.83\text{ per hour}$

Now, Labor will get 95% overhead rate

⇒ The labor is getting 100% already but an overhead of 95% is also given

$\text{So, Hourly Rate = }\frac{23.83}{1+0.95}\\\\\bf\implies\textbf{Hourly Rate = }\$12.22\textbf{ per hour}$

3 0

4 years ago

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0

Tom [10]

Answer:

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

Step-by-step explanation:

The given equation is

$(2x+3)^2+8(2x+3)+11=0$

Let us treat this as a quadratic equation in $(2x+3)$ .

where $a=1,b=8,c=11$

The solution is given by the quadratic formula;

$(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute these values into the formula to obtain;

$(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}$

$(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}$

$(2x+3)=\frac{-8\pm \sqrt{20} }{2}$

$(2x+3)=\frac{-8\pm2\sqrt{5} }{2}$

$(2x+3)=-4\pm \sqrt{5}$

$(2x+3)=-4-\sqrt{5}$ or $(2x+3)=-4+ \sqrt{5}$

$2x=-3-4-\sqrt{5}$ or $2x=-3-4+ \sqrt{5}$

$2x=-7-\sqrt{5}$ or $2x=-7+ \sqrt{5}$

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

5 0

4 years ago

Explain how you would graph 3x+9y= -18 without converting to slope-intercept form

Zolol [24]

Answer:

you would solve using x and y intercepts.

Step-by-step explanation:

for the X intercept, Y=0

3x=-18. you divide by three on both sides

x=-6. (-6,0)

the for the y intercept, X=0

+9y=-18. you divide 9 on both sides.

y=-2. (0,-2)

then you graph both and connect the points on the x and y axis.

Brainiest always accepted!!!!1

8 0

4 years ago

5. What type of quadrilateral is DEFG?<br> A square<br> B rhombus<br> trapezoid<br> D parallelogram

padilas [110]

Answer: DEFG is a parallelogram

Explanation:

7 0

3 years ago