Which statement is false?

Mathematics

2 answers:

natka813 [3]3 years ago

8 0

The answer is the 3rd option

anastassius [24]3 years ago

8 0

Answer:

Step-by-step explanation:

all squares are rhombuses but not all rhombuses are squares

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A triangle has side lengths of 24 in., 32 in., and 40 in. Is the triangle acute, obtuse, or right? A) right. B) obtuse. C) acute

Feliz [49]

24, 32 , 40. Divide through by 8

3, 4, 5,

The 3 , 4, 5 reminds of the Pythagorean triple, which is a right angled triangle.

So a triangle with sides 24, 32, 40 is a right angled triangle.

Option A.

8 0

3 years ago

Read 2 more answers

The quotient of

vova2212 [387]

$\displaystyle{ \frac{y^2-16}{4y-16} \div \frac{y+4}{16y}= \frac{y^2-16}{4y-16}\cdot\frac{16y}{y+4}\\\\$

$\displaystyle{ = \frac{y^2-4^2}{4(y-4)} \cdot\frac{16y}{y+4}= \frac{(y-4)(y+4)}{4(y-4)}\cdot\frac{16y}{y+4} = \frac{16y}{4}=4y$

Answer: 4y

Remark: $y^2-4^2=(y-4)(y+4)$ by the difference of squares identity, or formula.

6 0

3 years ago

Assume that Thermometer readings are normally distributed with a mean of 0°C and standard deviation of 1.00°C. A Thermometer is

Ne4ueva [31]

Answer:

0.2857

Step-by-step explanation:

The probability of interest is the area under the probability density curve between the z-values associated with the temperature limits of interest.

The first attachment shows a "sketch" of the distribution and the area of the portion of interest. (It also shows the probability as 0.2858.)

The second attachment shows the table values of interest for this problem. The z-values that we want to look for in the table are ...

z1 = (0.50° -0°)/1.00° = 0.50

and

z2 = (2.00° -0°)/1.00° = 2.00

The area of the probability density function to the left of each of these z-values is given in the table, so the area between them is the difference of table values:

0.9772 -0.6915 = 0.2857

The probability of a reading between 0.50 and 2.00 is about 0.2857.