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iren [92.7K]
3 years ago
13

Mrs. jack bought 150 T-shirt for $1920 from a factory calculate the cost of one T-shirt

Mathematics
2 answers:
o-na [289]3 years ago
6 0

Answer: $12.80

Step-by-step explanation:

$1980/ 150 t shirts =$12.80 per shirt

grandymaker [24]3 years ago
6 0

Answer:

$12.80 for every T-shirt.

Step-by-step explanation:

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In science class, the average score on a lab report is 82 points, with all students scoring within 3.2 points of the average. If
nirvana33 [79]

An equation that represents the minimum and maximum scores is; |x - 82| = 3.2.

<h3>How to write an absolute value equation?</h3>

The absolute value function is defined by:

f(x) = x, x ≥ 0.

f(x) = x, x < 0.

It measures the distance of a point x to the origin.

For this problem, the distance between the minimum and the maximum scores and the mean is of 3.2, that is, the difference between these scores x and the mean of 82 is of 3.2, hence the absolute value equation that represents this situation is given by:

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7 0
2 years ago
At the candy store there are 420 gumdrops and 280 chocolate bars, for a total of 700 candies all together. What is the ratio of
Mekhanik [1.2K]

Answer:

5 : 2

Step-by-step explanation:

Given that:

Number of gumdrops = 420

Number of chocolate bars = 280

Total Number of candies = 700

To find:

The ratio of candies to chocolate bars = ?

Solution:

First of all, let us discuss the method to find the ratio of any two quantities.

Suppose, we need to find the ratio of two numbers p and q.

Then to find the ratio p:q , we need to divide p by q and represent it in the simplest form \frac{a}{b} such that a and b can not be divided further.

Here, to find the ratio of candies to chocolate bar:

Ratio = \dfrac{\text{Number of candies}}{\text{Number of chocolate bars}}\\\Rightarrow \dfrac{700}{280}

Here, we can simplify the fraction by dividing the numerator and denominator by 10 first:

\dfrac{70}{28}

Now, let us divide the numerator and denominator by 14:

\dfrac{5}{2}

So, the ratio is <em>5 : 2</em>

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3 years ago
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