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777dan777 [17]
3 years ago
14

A triangle has side lengths of 24 in., 32 in., and 40 in. Is the triangle acute, obtuse, or right? A) right. B) obtuse. C) acute

Mathematics
2 answers:
Feliz [49]3 years ago
8 0
24,  32 ,  40.           Divide through by 8

3,    4,    5,            

The 3 , 4, 5 reminds of the Pythagorean triple, which is a right angled triangle.

So a triangle with sides 24, 32, 40 is a right angled triangle.

Option A.  
babunello [35]3 years ago
5 0
To answer the question above, take note of the relationship between the square of the longest side to that of the sum of the square of the two shorter sides.
                                    a² + b² _ c²
                           24² + 32² = 1600    ; 40² = 1600
Since they are equal, the triangle formed is a right triangle. 

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A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
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Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

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