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Liula [17]
3 years ago
8

If mSW = (12x-5)°, mTV= (2x+7)°,and m angle TUV = (6x-19)°, find mSW

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Given:

Consider the below figure attached with this question.

m(arc(SW)) = (12x-5)°, m(arc(TV))= (2x+7)°,and measure of angle TUV = (6x-19)°.

To find:

The m(arc SW).

Solution:

Intersecting secant theorem: If two secants intersect outside the circle, then the angle on the intersection is half of the difference of the larger subtended arc and smaller subtended arc.

Using Intersecting secant theorem, we get

m\angle TUV=\dfrac{1}{2}(m(arc(SW))-m(arc(TV)))

6x-19=\dfrac{1}{2}((12x-5)-(2x+7))

6x-19=\dfrac{1}{2}(12x-5-2x-7)

6x-19=\dfrac{1}{2}(10x-12)

Multiply both sides by 2.

2(6x-19)=10x-12

12x-38=10x-12

12x-10x=38-12

2x=26

Divide both sides by 2.

x=13

Now, the measure of arc SW is:

m(arc(SW))=(12x-5)^\circ

m(arc(SW))=(12(13)-5)^\circ

m(arc(SW))=(156-5)^\circ

m(arc(SW))=151^\circ

Therefore, the measure of arc SW is 151 degrees.

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a 40 ounce bag

Step-by-step explanation:

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a seed company says that 4 out of every 5 of its seeds will grow.if Madi plants 40 of these seed, then how many seeds is Madi ex
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38 seeds will grow

Step-by-step explanation:

4/5 = 80%

80% = .8

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An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What
galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\      P(A)=\frac{5}{66}=0.075757576

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

P(D_i)=\frac{1}{6} for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}

P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}

P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}

P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}

P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}

P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0

Part A:

The probability that all of the balls selected are white:

P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)

P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\      P(A)=\frac{5}{66}=0.075757576

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find P(D_3|A)

The data required is calculated above:

P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516

7 0
3 years ago
What is the value of x in the equation 4x+8y=40, when y=0.8?
lubasha [3.4K]
4x+8y=40
0.8*8=6.4
4x+6.4=40
40-6.4=33.6
4x=33.6
33.6\4=8.4
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3 years ago
How do I do this? I don’t understand
Ganezh [65]
You have to input the 5 into the x place. so it would be y=3(5) and you get the answer y=15
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