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yarga [219]
3 years ago
11

HELP!what is the y-intercept of the function f(x)=5*(1/6)^x

Mathematics
1 answer:
vivado [14]3 years ago
5 0

Answer:

The y intercept is (0,5)

Step-by-step explanation:

f(x) = 5 * (1/6)^x

What is the y intercept?  Let x = 0

f(0) = 5 * (1/6)^0

f(0) = 5*1 = 0

The y intercept is (0,5)

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"if the standard deviation of a group of 20 scores is 15, what is the variance?"
DerKrebs [107]

We have been given that the standard deviation of a group of 20 scores is 15 and we are asked to find variance.

Since we know variance is square of standard deviation. In order to find out the variance of the given data we have to take the square of 15.

\text{ Variance}=\sigma^{2}\\
=15^{2}=225

Therefore, our variance is 225.


7 0
3 years ago
In the Triangle below, find X <br> A. 10.3<br> B. 9.6<br> C. 84<br> D. 9
viva [34]
Isosceles triangle
9x + 3 = 84
9x = 81
  x = 9

answer
<span>D. 9</span>
4 0
3 years ago
In angle abc , m angle A =x , m angle B =2x+2, m angle C = 3x+4.what is value x
Morgarella [4.7K]
A + B + C = 180
x + 2x + 2 + 3x + 4 = 180
6x + 6 = 180
6x = 174
  x = 29
8 0
3 years ago
Greatest common factor of 4ax^2+4ax+4a
Rina8888 [55]

Simplifying

4AX2 + 4AX + 4A = 0

Reorder the terms:

4A + 4AX + 4AX2 = 0

Solving

4A + 4AX + 4AX2 = 0

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), '4A'.

4A(1 + X + X2) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'A' equal to zero and attempt to solve:

Simplifying

A = 0

Solving

A = 0

Move all terms containing A to the left, all other terms to the right.

Simplifying

A = 0

Subproblem 2

Set the factor '(1 + X + X2)' equal to zero and attempt to solve:

Simplifying

1 + X + X2 = 0

Solving

1 + X + X2 = 0

Move all terms containing A to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + X + -1 + X2 = 0 + -1

Reorder the terms:

1 + -1 + X + X2 = 0 + -1

Combine like terms: 1 + -1 = 0

0 + X + X2 = 0 + -1

X + X2 = 0 + -1

Combine like terms: 0 + -1 = -1

X + X2 = -1

Add '-1X' to each side of the equation.

X + -1X + X2 = -1 + -1X

Combine like terms: X + -1X = 0

0 + X2 = -1 + -1X

X2 = -1 + -1X

Add '-1X2' to each side of the equation.

X2 + -1X2 = -1 + -1X + -1X2

Combine like terms: X2 + -1X2 = 0

0 = -1 + -1X + -1X2

Simplifying

0 = -1 + -1X + -1X2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Solution

A = {0}

3 0
3 years ago
Read 2 more answers
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find
Nonamiya [84]

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

<h3>How to find the Tension in Suspended Cables?</h3>

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

Read more about Tension in Cables at; brainly.com/question/11653585

#SPJ1

7 0
2 years ago
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