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statuscvo [17]
3 years ago
6

In an inductive generalization, in order to achieve an error margin of plus or minus 3 percentage points at a confidence level o

f about 95 percent, whats the smallest random sample we can get away with, regardless of the size of the target population
Mathematics
1 answer:
ANTONII [103]3 years ago
6 0
Let n =  required random sample size.

Assume that the population standard deviation is known as σ.
Let m =  sample mean.
At the 95% confidence level, the expected range is
(m - k(σ/√n), m + k(σ/√n))
where k = 1.96.

Therefore the error margin is 1.96(σ/√n).
Because the error margin is specified as 3% or 0.03, therefore
(1.96σ)/√n = 0.03
√n = (1.96σ)/0.03
n = 128.05σ²

This means that the sample size is about 128 times the population variance.

Answer:
Smallest sample size = 128.05σ², where σ = population standard deviation.
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A. \triangleDEF where \angle D = 75^{\circ} and \angle E = 20^{\circ}.

Step-by-step explanation:

At first we must keep in mind that two triangles are similar when they have same angle configuration, that is, each pair of angles is congruent. If \triangleABC and \triangleDEF, then \angle A \equiv \angle D and \angle B \equiv \angle E. Hence, \angle D = 75^{\circ} and \angle E = 20^{\circ}.

In a nutshell, correct answer is A.

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Step-by-step explanation:

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The formula used in the compound interest calculator is A = P(1+r/n)(nt)

A = the future value of the investment

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