All categories

2 years ago

PLZZ HELP HAVE NO TIM!!

Mathematics

2 answers:

evablogger [386]2 years ago

8 0

Answer:

option 1

Step-by-step explanation:

its early, typo lol

12345 [234]2 years ago

3 0

The first one. X is greater than or equal to -1

You might be interested in

What is v6/v5 in simplest radical form?

ira [324]

Answer: $\sqrt{30}/5$

Step-by-step explanation:

You should get this answer because the simpliest form of a radical is that you shouldn't have any radical in the denominator. In order to get rid of the radical sign in the denominator, you have to multiply the numerator and the denominator with the $\sqrt{5}$ .

Look at the image below for further explanation

Download pdf

6 0

2 years ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (3, 1, 0) and perpendicu

iren2701 [21]

Answer with Step-by-step explanation:

We are given that a point (3,1,0)

Two vectors are

A=<1,1,0>

B=<0,1,1>

$A\times B=\begin{vmatrix}i&j&k\\1&1&0\\0&1&1\end{vmatrix}$

$A\times B=i-j+k$

Let v $=A\times B=i-j+k$

$v==$

$r_0==$

$r=r_0+vt$

Substitute the values then we get

$r=+t$

$r=$

The parametric equation of the line

$x=x_0+at,y=y_0+bt,z=z_0+ct$

Using the formula

The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

$x=3+t,y=1-t,z=t$

The symmetric equation of the line is given by

$\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$

Using the formula

The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

$\frac{x-3}{1}=\frac{y-1}{-1}=z$

8 0

3 years ago

P (2, 3) and Q (6, 10) are two points on the Cartesian plane.

lara31 [8.8K]

Step-by-step explanation:

Given:

$(x_1, \: y_1 ) =(2, \:3)\:\:\&\:\: (x_2, \: y_2) =(6, \:10)$

$l(PQ) = \sqrt{ {(x_1 - x_2)}^{2} + {(y_1 - y_2)}^{2}} \\ \\ = \sqrt{ {(2 - 6)}^{2} + {(3 - 10)}^{2}} \\ \\ = \sqrt{ {( - 4)}^{2} + {( - 7)}^{2}} \\ \\ = \sqrt{16 + 49} \\ \\ = \sqrt{65} \\ \\ \therefore \purple{ \boxed{ l(PQ) = 8.06 \: units}}\\\\$

Let S be the mid-point of PQ.

$\therefore S = \{\frac{x_1+x_2}{2}, \:\:\frac{y_1+y_2}{2}\} \\\\= \{\frac{2 +6}{2}, \:\:\frac{3+10}{2}\} \\\\= \{\frac{8}{2}, \:\:\frac{13}{2}\} \\\\\therefore S= \{4, \:\:6.5\} \\\\$

Equation of line PQ is given as:

$\frac{y-y_1}{y_1 - y_2}=\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-3}{3 - 10}=\frac{x-2}{2 - 6} \\\\\therefore \frac{y-3}{-7}=\frac{x-2}{-4} \\\\\therefore \frac{y-3}{7}=\frac{x-2}{4} \\\\\therefore 4(y-3)=7(x-2)\\\\\therefore 4y-12=7x-14\\\\\therefore 7x-14 - 4y + 12=0\\\\\red{\boxed {\therefore 7x-4y - 2 =0}}$

4 0

3 years ago

Read 2 more answers

15 cm<br> 8 cm<br> 6 cm<br> Find the area

DaniilM [7]

Answer:

The answer is 720

Step-by-step explanation:

15*8*6=720

Hope this helps!!

5 0

2 years ago

How do you solve formulas and literal equations for a variable?

Anni [7]

Answer:

Move the variables to one side and the constants to the other through subtraction/additions to BOTH SIDES. Then, divide/multiply to get x = some constant.

Step-by-step explanation:

Try Khan Academy.

7 0

2 years ago