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3 years ago

5

Can u help me do this

1 answer:

chubhunter [2.5K]3 years ago

5 0

There will be 2 books left over if he fills each box.
7 · 4 = 28
30 - 28 = 2

Good Luck

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What is the equation of the directrix of the parabola given by the equation (y − 3)2 = 8(x − 5)?

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The answer is x=3. HOPE THIS HELPS!!!!!!!!!!!!!

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3 years ago

The cost price of a box and a pen is Rs 80 The box is sold at 10% profit and the pen is sold at 20% loss. If the selling price o

uysha [10]

Answer:

61.84%

Step-by-step explanation:

Let the cost of the box be x. Since the price of the box and the pen is Rs 80, the pen's price can be represented as 80 - x. The box is sold at a ten percent profit, and an added ten percent is equal to 1.1. Therefore, the price the box sells at is 1.1(x). A 20% loss is the same a keeping 80% or multiplying by 0.8. This means the pen sold at 0.8(80 - x). Now, we are given the box went for Rs 28 more than the pen, so we can create an equation:

1.1x = 0.8(80 - x) + 28

We can simplify and solve:

1.1x = 64 - 0.8x + 28

1.9x = 92

x = 92/1.9

x = 920/19

The cost of the box after the increase would be 1.1(920/19) and the pen would be 0.8(80 - 920/19).

The sum of these two can be written as a percent x of 80.

80x = 0.8(80 - 920/19) + 1.1(920/19)

80x = 64 - 0.8(920/19) + 1.1(920/9)

80x = 64 - 0.3(920/19)

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4 0

3 years ago

An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

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3 years ago

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The thousandth place is the 3rd digit after the decimal.

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3 years ago

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