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Unfortunately, no one buys your bracelets at a price of $10. this is a signal for you to _____. make more bracelets lower your p

tamaranim1 [39]

I would think you would lower ur price. But I wouldn't make the price so low so that it costs the same to produce them as it does to sell them, because then there would be no profit.

3 0

4 years ago

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300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do

katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0

3 years ago

The table lists recommended amounts of food to order for

Otrada [13]

Lasagna: 25 5/8 (mixed number)

Deli meats: 10 5/6 (also a mixed number)

for the fried chicken, my envision has 26 and yours has 24 so I sadly can't help w that but if you press "question help" and press "view an example" it'll teach you how to do it

3 0

3 years ago

Factor Completely x^4-2x^2y^2+y^4

12345 [234]

<h3>Answer :</h3>

$\bf (x+y)^2(x-y)^2$

==============

<h3>Solving Steps:</h3>

===============

$\rightarrow \sf x^4-2x^2y^2+y^4$

<u>breakdown</u>

$\rightarrow \sf x^4-x^2y^2-x^2y^2+y^4$

<u>factor common term</u>

$\rightarrow \sf x^2(x^2-y^2)-y^2(x^2-y^2)$

<u>collect in groups</u>

$\rightarrow \sf (x^2-y^2)(x^2-y^2)$

<u>apply difference between two square method:</u> x² - y² = (x+ y)(x-y)

$\rightarrow \sf (x+y)(x-y) (x+y)(x-y)$

<u>simplify</u>

$\rightarrow \sf (x+y)^2(x-y)^2$

7 0

2 years ago

HELLLLPPPPPP PLEASEEEEEEEE....

oee [108]

For this case we have the following system of equations:
5x + 3y = 17
-8x - 3y = 9
The solution to this system can be written in matrix form as:
Ax = b
Where, A is a matrix that is given by:
A = [5 3; -8 -3]
The determinant of this matrix 2 * 2 is given by:
lAl = (5) * (- 3) - (3) * (- 8)
lAl = -15 - (-24)
lAl = -15 + 24
lAl = 9
Answer:
The determinant for solving this linear system is:
lAl = 9

5 0

3 years ago

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