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3 years ago

10

Car A covers 100 miles in 120 minutes, while car B covers 300 miles in 5 hours. How do car A and car B speeds compare (Hint: 60

minutes = 1 hour)
A. Car A is faster than car B.
B. Car B is faster than car A.
C. Car B is slower than car A.
D. Car A has the same speed as car B.

1 answer:

Korolek [52]3 years ago

5 0

Answer:

option D. Car A has the same speed as car B.

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3 years ago

A steel safe with mass 2200 kg falls onto concrete. Just

Virty [35]

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

The magnitude of the force exerted on the safe by the concrete on the is approximately $\underline{29.\overline 3 \, \mathrm{MN}}$

The concrete exerts a <u>force</u> that is approximately <u>1,359.16 times the weight of the safe</u>.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

$\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}$

$\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules$

Work done by concrete, W = Force, F × Distance, d

$\displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}$

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, <em>d</em>, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

$\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN$

The force of the concrete on the safe = $\underline{29.\overline 3 \ MN}$

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

$\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}$

The <u>force</u> exerted by the concrete is approximately <u>1,359.16 times the weight of the safe</u>.

Learn more here:

brainly.com/question/21060171

5 0

3 years ago

if all 10 players scored the same number of points, how many would each have to score to get a total of 230

Aliun [14]

Answer:

<u>Each player would have to score 23 points.</u>

Step-by-step explanation:

To answer this question, you must do 230 ÷ 10!

The answer to this is 23.

You can double check your answer by multiplying 23 by 10!

3 0

2 years ago