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dem82 [27]
3 years ago
8

14.12 = 1/2 (3.6x - 12.8) show work

Mathematics
2 answers:
katovenus [111]3 years ago
8 0

Answer:

11.4

Step-by-step explanation:

14.12= 1/2(3.6x-12.8)

14.12=1.8x-6.4

20.52=1.8x

x=11.4

Hope that helps :)

Lemme know if I need to explain more

Sergio039 [100]3 years ago
4 0

Answer:

x = 11.4

Step-by-step explanation:

14.12 = \frac{1}{2} ( 3.6x - 12.8 )

Rewrite so that the equation is entirely in decimals;

14.12 = 0.5( 3.6x - 12.8 )

Distribute;

14.12 = 1.8x - 6.4

Inverse operations;

14.12 = 1.8x - 6.4

+6.4            +6.4

20.52 = 1.8x

/1.8        /1.8

11.4 = x

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Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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