Answer:
cot(θ)=5/12
Step-by-step explanation:
(I'm going to replace theta with x to save time.)
Recall that sine is equal to opposite over hypotenuse. Thus:
sin(x)=12/13, this means that the opposite side is 12 while the hypotenuse is 13 (well, it doesn't have to be, but their ratios are).
Find the adjacent side using the Pythagorean Theorem.
13^2 = 12^2 + adj^2
adj^2 = 25
adj = 5.
Recall that tan(x) is opposite over adjacent. This means that cot(x) is adjacent is opposite.
Therefore: cot(x) = 5/12.
Answer:
Through any three non collinear points(The points which do not lie on the same line ), there exists exactly one plane.
Step-by-step explanation:
We have given the postulate:
"Through three points there exists one line."
According to the three point postulate:
Through any three non collinear points(The points which do not lie on the same line ), there exists exactly one plane.
Through three non-collinear points X,Y,Z there exists exactly one plane.
The plane XYZ contains atleast three non collinear points...
Answer:
Step-by-step explanation:
Let x represent the amount of medical bills that Giselle has to pay.
Assume she has over $160 in bills,
it means that
x > 160
Under plan A, Giselle would have to pay the first $110 of her medical bills, plus 35% of the rest. Therefore, she will have to pay for
35/100 × (x - 110) = 0.35(x - 110)
Under plan B, Giselle would pay the first $160, but only 20% of the rest. Therefore, she will have to pay for
20/100 × (x - 160) = 0.2(x - 160)
Therefore, the amount of medical bills that plan B will save is
0.35(x - 110) - 0.2(x - 160) = 0.35x - 38.5 - 0.2x + 32
0.15x + 6.5
Substituting x = 160 into 0.15x + 6.5, it becomes
0.15 × 160 + 6.5 = $30.5
Total bills would be 160 + 30.5 = 190.5
Therefore, Giselle would save $30.5 with plan B if she had more than $190.5 in bills.
121/400 is already in simplest form.
Answer:
The answer is "
"
Step-by-step explanation:
Please find the graph file.
![h= y=2x-x^2\\\\r= x\\\\Area=2\pi\times r\times h\\\\= 2 \pi \times x \times (2x-x^2)\\\\= 2 \pi \times 2x^2-x^3\\\\volume \ V(x)=\int \ A(x)\ dx\\\\= \int^{x=1}_{x=0} 2\pi (2x^2-x^3)\ dx\\\\= 2\pi [(\frac{2x^3}{3}-\frac{x^4}{4})]^{1}_{0} \\\\= 2\pi [(\frac{2}{3}-\frac{1}{4})-(0-0)] \\\\= 2\pi \times \frac{5}{12}\\\\=\frac{5\pi}{6}\\\\](https://tex.z-dn.net/?f=h%3D%20y%3D2x-x%5E2%5C%5C%5C%5Cr%3D%20x%5C%5C%5C%5CArea%3D2%5Cpi%5Ctimes%20r%5Ctimes%20h%5C%5C%5C%5C%3D%202%20%5Cpi%20%5Ctimes%20x%20%5Ctimes%20%282x-x%5E2%29%5C%5C%5C%5C%3D%202%20%5Cpi%20%5Ctimes%202x%5E2-x%5E3%5C%5C%5C%5Cvolume%20%5C%20V%28x%29%3D%5Cint%20%5C%20A%28x%29%5C%20dx%5C%5C%5C%5C%3D%20%5Cint%5E%7Bx%3D1%7D_%7Bx%3D0%7D%202%5Cpi%20%282x%5E2-x%5E3%29%5C%20dx%5C%5C%5C%5C%3D%202%5Cpi%20%5B%28%5Cfrac%7B2x%5E3%7D%7B3%7D-%5Cfrac%7Bx%5E4%7D%7B4%7D%29%5D%5E%7B1%7D_%7B0%7D%20%5C%5C%5C%5C%3D%202%5Cpi%20%5B%28%5Cfrac%7B2%7D%7B3%7D-%5Cfrac%7B1%7D%7B4%7D%29-%280-0%29%5D%20%5C%5C%5C%5C%3D%202%5Cpi%20%5Ctimes%20%5Cfrac%7B5%7D%7B12%7D%5C%5C%5C%5C%3D%5Cfrac%7B5%5Cpi%7D%7B6%7D%5C%5C%5C%5C)
