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siniylev [52]
3 years ago
6

What is the area of the triangle? A. 26.91 cm² B. 28.98 cm² C. 53.82 cm² D. 57.96 cm²

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
A= hᵇb
       2
hope that helped at all.

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A 30% increase followed by a 15% decrease, is it greater than original, smaller or same as
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I believe the correct answer is greater than
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2 years ago
(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)
klemol [59]

Answer:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

Step-by-step explanation:

Given the expression

\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)

Remove parentheses:  (a)=a

=-t^4-5t^3-10t^2+9t^3+3t^2-1

Group like terms

=-t^4-5t^3+9t^3-10t^2+3t^2-1

Add similar elements        

=-t^4-5t^3+9t^3-7t^2-1         ∵ -10t^2+3t^2=-7t^2

Add similar elements        

=-t^4+4t^3-7t^2-1                  ∵  -5t^3+9t^3=4t^3

Thus, the equivalent expression in simplified form:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

4 0
3 years ago
In triangle XYZ, let angle Y be a right angle, mZ = 54°, and YZ = 361. Find the area of the
laiz [17]

Answer:

89,709

Step-by-step explanation:

∡Z= 54°

tan 54 = XY / 361

XY = 361 · tan 54°

XY = 497

A = 1/2 (361) (497)

5 0
2 years ago
Pythagorean triples are super important to know. If the hypotenuse of a triangle is 15, what are its legs ( hint - use the three
Triss [41]

Answer:

9, 12

Step-by-step explanation:

Just multiply the 3,4,5 triple by 3 and u get 9, 12, 15

8 0
2 years ago
Please Help!!<br><br>Use Euler’s formula to write in exponential form.
LekaFEV [45]

Answer:

C, 4e^{i(7\pi/4)}

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

e^{ix}=\cos{x}+i\sin{x}

Given the complex number 2\sqrt{2}-2i\sqrt{2}, we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression 2(\sqrt{2}-i\sqrt{2})

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression 4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right) , and <em>now </em>we have something to work with.

Looking back at Euler's formula e^{ix}=\cos{x}+i\sin{x}, we can map our expression inside the parentheses to the one on the right side of the formula, giving us \cos{x}=\frac{\sqrt2}{2} and \sin{x}=-\frac{\sqrt2}{2}, or equivalently:

\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x

At this point, we can look at the unit circle (attached) to see the angle satisfying these two values for sine and cosine is 7π/4, so x=\frac{7\pi}{4}, and we can finally replace our expression in parentheses with its exponential equivalent:

4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}

Which is c on the multiple choice section.

4 0
3 years ago
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