Answer: Part 1: The reaction is considered as replacement reaction and produce preciptate.
Part 2: Due to Mg is more active than Al.
Explanation:
Part 1: the reaction is replacement reaction due to the ions is replaced with each other as this equation shows:
MgCl2 + Na2CO3 → MgCO3 + 2NaCl
and MgCO3 is a white precipitate.
Part 2:
Al reacts with CuCl2 because Al is more active than Cu.
Al can not react with MgCl2 because Mg is more active than Al.
The answer is SiO2
Since silicon has four valence electrons and each oxygen has 2, for every 1 silicon there must be 2 oxygen to fill in both element's outer shells satisfactorily. An alternative way to figure out the chemical formula is to simply swap the charges.
Silicon is a -4 and oxygen is a -2.
Oxygen's charge is brought down into subscript and set as the number of silicons in the chemical formula, making silicon Si2. Silicon's charge is brought down to make the number of oxygens in the chemical formula O4. The formula we have currently is Si2O4. Simplify it to get the empirical formula (divide by 2) and you get SiO2.
In bleaching a stain, you see that the stain fades, and doesn't come back, which indicates that it has undergone a change.
Buring a match, you would see the ashes, and that it cannot be it's original substance again.
In rusting of an iron nail, the nail cannot be unrusted easily, which indicates that it has been through a chemical reaction.
Answer:
ok so the answer is
4(energy)
5(kinetic energy)
6(potential energy)
7(gravity)
8(work)
Explanation:
I already learned this last year.
The balanced equation for the reaction is
C₃H₈ + 5O₂ → 3CO₂ + 4H₂<span>O
Moles (mol) = mass (g) / molar mass (g/mol)
Mass of the </span>C₃H₈ = 0.025 g
Molar mass of C₃H₈ = <span>44.1 g/mol
Hence, moles of </span>C₃H₈ = 0.025 g / 44.1 g/mol = 5.67 x 10⁻⁴ mol
The stoichiometric ratio between C₃H₈ and O₂ is 1 : 5.
Hence, moles of O₂ = moles of C₃H₈ x 5
= 5.67 x 10⁻⁴ mol x 5
= 2.835 x 10⁻³ mol
Molar mass of O₂ = <span>32.00 g/mol
Hence, mass of O</span>₂ = moles x molar mass
= 2.835 x 10⁻³ mol x 32.00 g/mol
= 0.09072 g
Hence, needed O₂ for the reaction is 0.09072 g.