The ph of a saturated solution of Ca(OH)2 is 12.35
CALCULATION:
For the reaction
Ca(OH)2 → Ca2+ + 2OH-
we will use the Ksp expression to solve for the concentration [OH-] and then use the acid base concepts to get the pH:
Ksp = [Ca2+][OH-]^2
The listed Ksp value is 5.5 x 10^-6. Substituting this to the Ksp expression, we have
Ksp = 5.5 x 10^-6 = (s) (2s)^2 = 4s^3
s3 = 5.5x10^-6 / 4
Taking the cube root, we now have
s = cube root of (5.5x10^-6 / 4)s
= 0.01112
We know that the value of [OH-] is actually equal to 2s:
[OH-] = 2s = 2 * 0.01112 = 0.02224 M
We can now calculate for pOH:
pOH = - log [OH-]
= -log(0.02224)
= 1.65
Therefore, the pH is
pH = 14 - pOH
= 14 - 1.65
= 12.35
1.34*10^6
Move the decimal 6 times to the left, it is a number 1-10
The question is: Give the systematic name of 
.
Answer: The systematic name of is diphosphorus trisulfide.
Explanation:
As the chemical formula of given compound is . This sows that there are two phosphorus atoms so a prefix "di" will be added before the name of phosphorus atom.
Whereas there are three sulfur atoms present here. So, a prefix "tri" will be added before naming the sulfur atom. As sulfur is the anion so a suffix '-ide' will be added to its name.
Hence, name of the compound is diphosphorus trisulfide.
Thus, we can conclude that the systematic name of is diphosphorus trisulfide.
