Ask question

Ask question

All categories

3 years ago

9

When should you use multiplication to solve a system of linear equations by elimination

1 answer:

stich3 [128]3 years ago

4 0

To use the elimination method you need the same variable in each equation to have the same coefficient. If neither variable has the same coefficient in each equation, you need to multiply one or both of the equations by a constant to get the same coefficient.

You might be interested in

Help me with the ones you are able to do. Please:((

igor_vitrenko [27]

Answer:

5. $16.8 6.$16.7 7. 4 costumes 8. no because the slope isn't one 9. 28.8

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the square root of 17.64?

Debora [2.8K]

Answer:

4.2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need this soon, please.

leonid [27]

Answer:

5 10

12 5

Step-by-step explanation:

you add numbers in the same position.

2+3. 4+6

7+5. 5+2

5 0

3 years ago

Katie said, "Negative numbers are integers". What was her error?

Sunny_sXe [5.5K]

Negative numbers are integers.The set of integers include negative numbers, positive numbers, and zero

6 0

3 years ago

Write the first five terms of the sequence defined by the explicit formula.

AlexFokin [52]

Answer:

(a) 112, 28, 7, (7/4), (7/16)

Step-by-step explanation:

The sequence is given by the explicit formula

$a_{n} = 112 (\frac{1}{4} )^{n-1}$

The terms of the sequence are :

$a_{1} = 112 (\frac{1}{4} )^{1-1} = 112 (\frac{1}{4} )^{0} =112$

$a_{2} = 112 (\frac{1}{4} )^{2-1} = 112(\frac{1}{4} ) =28$

$a_{3} = 112 (\frac{1}{4} )^{3-1} = 112(\frac{1}{4} )^{2} = 7$

$a_{4} = 112 (\frac{1}{4} )^{4-1}=112(\frac{1}{4} )^{3} = \frac{7}{4}$

$a_{5} = 112 (\frac{1}{4} )^{5-1}=112 (\frac{1}{4} )^{4} = \frac{7}{16}$

6 0

3 years ago