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professor190 [17]

3 years ago

14

I need this soon, please.

1 answer:

leonid [27]3 years ago

5 0

Answer:

5 10

12 5

Step-by-step explanation:

you add numbers in the same position.

2+3. 4+6

7+5. 5+2

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A kayaker can paddle 12 mi in 2 h moving with the river current. Paddling at the same pace, the trip back against takes 4 h. Ass

Firdavs [7]

Downstream DATA:
distance = 12 miles
time = 2 hours
rate = 12/2 = 6 mph
----------------
Upstream DATA:
distance = 12 miles
time = 4 hrs
rate = 12/4 = 3 mph
----
Equations:
Downstream: b + c = 6
Upstream::: b - c = 3
------
Add to get:
2b = 9
b = 4.5 mph (speed of the boat in still water.)
-----
Solve for "c":
b + c = 6
4.5 + c = 6
c = 1.5 mph (speed of the current)
The answer is 1.5 mph

7 0

3 years ago

What is 48 divided by 0.08

Inessa [10]

48 ÷ 0.08 = 600
check 600 × 0.08= 48

6 0

3 years ago

Please help with this

Radda [10]

Answer:

2. No

3. Yes

4. Yes

5. Yes

6. No

7. Yes

3 0

3 years ago

Read 2 more answers

Please im so confused and lazy

grandymaker [24]

Answer:x=9

Step-by-step explanation:

6x+25=79

-25 -25

6x=54

/6 /6

x=9

7 0

2 years ago

Read 2 more answers

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago