D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
B) Subtract 12-4 to calculate the range of this data set
there are 4 eggs total 3 plain and 1 gold
so you have a 1/4 probability of picking the gold egg
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course hero problems<span>
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username: helpforstudents
password: 2248helpforstudents
remember: no membership.
if problems say them to me, ok?
Answer:
it's a very easy one and it's answer is 1728
