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Paul [167]
3 years ago
9

A). Se pretende construir un invernadero, en un terreno que presenta una pendiente del 10%. Por lo tanto se requiere nivelarlo,

con el método de nivelación simple. Los datos que aparecen en la figura son los obtenidos en campo. Calcular;
.
a). El desnivel entre los puntos A y B.
b). La lectura que deberá tomarse en el punto B, si el nivel está correcto
Mathematics
1 answer:
zaharov [31]3 years ago
4 0

i think its a sorry if wrong

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One number is four more than twice another. Their sum<br> is 34. Find the numbers.
lianna [129]

x = 15

2x + 4 = 34

     -4     -4

<u>2x</u>       = <u>30</u>

2             2

X         = 15

5 0
3 years ago
F(x) = x2 + 1<br> g(x) = 5 – x
xz_007 [3.2K]

Answer:

g(x) = 5 – x

Step-by-step explanation:

7 0
3 years ago
What is the answer of this question ?
fgiga [73]

Answer:

the answer is B

Step-by-step explanation:

hoped I helped:)

6 0
3 years ago
Ryan took out a 66 month loan to pay for a 28500 car.if he paid 33829.50,in total at the end of the loan,find the interest rate
professor190 [17]

9514 1404 393

Answer:

  3.4%

Step-by-step explanation:

The total amount due is ...

  A = P(1 +rt/12) . . . . . principal P, annual rate r, t months

  33829.50 = 28500(1 +66/12r)

  1.187 = 1 +5.5r . . . . . divide by 28500, simplify

  0.185/5.5 = r = 0.034 = 3.4%

The interest rate on the loan is 3.4%.

3 0
3 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
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