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Lynna [10]
3 years ago
12

Consider a particle moving around a circle with a radius of 38cm. It rotates from 10 degrees to 100 degrees in 11 seconds. Calcu

late the instantaneous velocity of the particle.
Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Step-by-step explanation:

Given that,

Radius of circle, r = 38 cm = 0.38 m

It rotates form 10 degrees to 100 degrees in 11 seconds i.e.

\theta_i=10^{\circ}=0.174\ rad

\theta_f=100^{\circ}=1.74\ rad

Let \omega is the angular velocity of the particle such that, \omega=\dfrac{\omega_f-\omega_i}{t}

\omega=\dfrac{1.74-0.174}{11}

\omega=0.142\ rad/s

We need to find the instantaneous velocity of the particle. The relation between the angular velocity and the linear velocity is given by :

v=r\times \omega

v=0.38\times 0.142

v = 0.053 m/s

So, the instantaneous velocity of the particle is 0.053 m/s. Hence, this is the required solution.  

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