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2 years ago

Please help meeeeeeeee

Mathematics

1 answer:

Olegator [25]2 years ago

4 0

Answer:

Step-by-step explanation:

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If sin ⁡x=7/25, and 0 < x < π/2, what is cos⁡(x−3π/2)?

Likurg_2 [28]

Answer:

$Cos(x-\frac{3\pi}{2})=-\frac{7}{25}$

Step-by-step explanation:

Remember that $cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

Then,

$cos(x-\frac{3\pi}{2})=cos(x)cos(\frac{3\pi}{2})+sin(x)sin(\frac{3\pi}{2})\\$

But $cos(\frac{3\pi}{2})=0$ and $sin(x)=\frac{7}{25}$

Then

$cos(x-\frac{3\pi}{2})=cos(x)*0+\frac{7}{25}*sin(\frac{3\pi}{2})\\=\frac{7}{25}*(-1)=\frac{-7}{25}$

5 0

3 years ago

- Plot two points to graph the second equation.

denis-greek [22]

Answer:

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Step-by-step explanation:

6 0

2 years ago

A pile of earth removed from an excavation is a cone measuring 6ft high and 30ft across its base. How many trips will it take to

nignag [31]

Answer: 14

Step-by-step explanation:

Given

Excavation cone measures

height $h=6\ ft$

Diameter $d=30\ ft$

Truck can dump $125\ ft^3$ at a time

The volume of a cone is

$V=\dfrac{1}{3}\pi r^2h$

Putting values

$\Rightarrow V=\dfrac{1}{3}\times \pi\times 15^2\times 6\\\Rightarrow V=1413.9\approx 1414\ ft^3$

No of trips(N) required to accumulate this much volume is given by

$\Rightarrow N=\dfrac{1414}{125}=13.3\approx 14$

Therefore, 14 trips are necessary to accumulate a cone of volume $1414\ ft^3$

8 0

2 years ago

How do I answer question b?

SCORPION-xisa [38]

The answer for that would be 2 raise to 5. solution:

2 ³ x 2 raise to 6 = 2 raise to 9
thus, you have now,
2 raise to 9 over 2 raise to 4

subtracting 4 from 9
the Answer is 2 raise to 5

7 0

3 years ago

I need help now assssssap

Andreyy89

Answer:

assssssssssssssap

Step-by-step explanation:

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7 0

2 years ago

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