I think its 166 so u divide 6.64 by 0.04
Answer:
Class width = 20
Approximate lower class limit of the first class = 110
Approximate Upper class limit of the first class = 119
Step-by-step Explanation:
The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.
Thus, class width = 130 - 110 = 20
The approximate lower class limit of the first class is the lowest score we have in the first class = 110
The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129
Answer: 7
Step-by-step explanation:
1 x 4 = 4
6+4= 10
10-3=7
3) We have
which has vertical asymptotes (i.e. infinite discontinuities) whenever the denominator is zero. This happens for
(where is any integer)
So the graph of has vertical asymptotes whenever and .
4) Given
we have the one-sided limits
and
The one-sided limits don't match, so the two-sided limit does not exist. In other words, the limit does not exist at because the function approaches different values from the left and right side of .
Lets say Priscillas's family total drove P miles.
and Clifton's family drove C miles
now Clifton drove half as far as Priscilla drove.
so C=P/2 this is the expression
If Priscilla drove total 135+40= 175miles
And Clifton drove C=175/2=87.5miles