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2 years ago

QUESTION ON PIC TY!!!

Mathematics

1 answer:

Degger [83]2 years ago

3 0

Answer:

Step-by-step explanation:

Multiply each number times 2 and then subtract from 29

3: 23

4: 21

5: 19

6: 17

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ABCD is a parallelogram. AB>AD. Prove: m∠ADB>m∠BDC. Show your work (statement reason maybe?)

Gwar [14]

In the parallelogram ABCD, join BD.

Consider the triangle Δ ABD.

It is given that AB > AD.

Since, in a triangle, angle opposite to longer side is larger, we have,

∠ ADB > ∠ ABD. --- (1)

Also, AB || DC and BD is a transversal.

Therefore,

∠ ABD = ∠ BDC

Substitute in (1), we get,

∠ ADB > ∠ BDC.

7 0

3 years ago

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If i have 18 apples and i get 1328 more how many apples would i have

devlian [24]

Darling, this problem is quite simply addition. You add 18 to 1328. 1328 + 18. we add the eights first. 8 + 8 equals 16. The 6 stays and we carry the one. 1 + 2 is 3. And then we add our carried 1 to make 4. So, the answer is 1346. I hope this helped!

6 0

4 years ago

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HOW DO YOU CONVERT SURFACE AREA TO VOLUME! HELP!!!! WILL MARK BRAINLIST!!

slamgirl [31]

Answer:

Formulas for a rectangular prism:

Volume of Rectangular Prism: V = lwh.

Surface Area of Rectangular Prism: S = 2(lw + lh + wh)

Space Diagonal of Rectangular Prism: (similar to the distance between 2 points) d = √(l2 + w2 + h2)

Step-by-step explanation:

Hope it helps :))))

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3 years ago

Andre cycled a distance 25km in 150 minutes. What was his average speed (km/h)?

FrozenT [24]

Answer:

10 km/h

Step-by-step explanation:

First, convert 150 minutes to hours:

150/60

= 2.5 hours

Then, to find his speed, divide the km by the number of hours:

25/2.5

= 10 km/h

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3 years ago

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A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30,

Flura [38]

Answer:

b) The margin of error is approximately 3.24

e) The critical value is 1.7921.

Step-by-step explanation:

Step(i):-

Given sample size 'n' =20

Given sample standard deviation 's' = 10

 Margin of error 

The margin of error is determined by

 $M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }$ 

The level of significance ∝ =0.95

The degrees of freedom = n-1 = 20-1=19

t₀.₉₅ = 1.729

$M.E = \frac{1.729 X10 }{\sqrt{20} }$

Margin of error = 3.866

Step(ii):-

 Margin of error 

The margin of error is determined by

 $M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }$ 

Given another sample size n =30

The level of significance ∝ =0.95

The degrees of freedom = n-1 = 30-1=29

t₀.₉₅ = 1.70

$M.E = \frac{1.7021 X10 }{\sqrt{30} } =3.24$

Margin of error = 3.24

5 0

3 years ago