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3 years ago

Can someone please help me solve 10y-2y=64

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

Answer:

y=8

Step-by-step explanation:

first you want to subtract 2y from 10y which will give you 8y and then divide both sides by 8 to get y alone and you will get y=8

Lemur [1.5K]3 years ago

4 0

Answer: y = 8

10y - 2y = 64

10 - 2 = 8

8y = 64

8y / 8 = 64 / 8

y = 8

<em>VERIFY:</em>

10(8) - 2(8) = 64

10 * 8 = 80

2 * 8 = 16

80 - 16 = 64

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zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

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$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

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inysia [295]

Answer:

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Step-by-step explanation:

Rewrite equations:

y=−x+3;y=x−1

Step: Solve

y=−x+3

Step: Substitute−x+3foryiny=x−1:

y=x−1

−x+3=x−1

−x+3+−x=x−1+−x(Add -x to both sides)

−2x+3=−1

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(Divide both sides by -2)

x=2

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y=−x+3

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