Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
In this question, the given functions are
And we have to find the value of
Which is equal to
So we have to subtract the two functions that is
Correct option is the second option .
This is wrong DONT use it
Answer: 6 and 1/4
Step-by-step explanation: To solve this problem, we first leave 5/2 alone so don't do anything to it.
For our second fraction, we want to switch the numerator and the
denominator which means find the reciprocal of it.
The reciprocal of 2/5 is just the opposite of it when
you flip it and it's going to be 5/2.
Because we did the opposite there, we need to do the opposite
of division and the opposite of division is multiplication.
So now we have 5/2 × 5/2 which is 25/4 or 6 and 1/4.
Answer:
f(n) = 74 + 11(n - 1)
<u>For the 7th term</u>
n = 7
f(7) = 74 + 11(7 - 1)
= 74 + 11(6)
= 74 + 66
<h2>= 140</h2>
<u>For</u><u> </u><u>the</u><u> </u><u>8</u><u>t</u><u>h</u><u> </u><u>ter</u><u>m</u>
n = 8
f(8) = 74 + 11( 8 - 1)
= 74 + 11(7)
= 74 + 77
<h2 /><h2>= 151</h2>
Hope this helps you