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nlexa [21]
3 years ago
13

Find the range for the function k(n) = 2n^2 when D = {–2, 1, 3}.

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0

Answer:

R = { 8, 2, 18}

Step-by-step explanation:

The range of the function is the set of function values or y-values. To find them, substitute the values x = -2, 1, and 3 into the function.

k(n) = 2n^2

k(-2) = 2(-2)^2

k(-2) = 2(4) = 8

k(n) = 2n^2

k(1) = 2(1)^2

k(1) = 2(1) = 2

k(n) = 2n^2

k(3) = 2(3)^2

k(3) = 2(9) = 18

The range is R = { 8, 2, 18}.

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