Find the range for the function k(n) = 2n^2 when D = {–2, 1, 3}.
1 answer:
Answer:
R = { 8, 2, 18}
Step-by-step explanation:
The range of the function is the set of function values or y-values. To find them, substitute the values x = -2, 1, and 3 into the function.
k(n) = 2n^2
k(-2) = 2(-2)^2
k(-2) = 2(4) = 8
k(n) = 2n^2
k(1) = 2(1)^2
k(1) = 2(1) = 2
k(n) = 2n^2
k(3) = 2(3)^2
k(3) = 2(9) = 18
The range is R = { 8, 2, 18}.
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