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Hoochie [10]
2 years ago
11

Whats the answer to 12.9 – 3.1) × 6.2 – 2 + 43

Mathematics
2 answers:
Grace [21]2 years ago
5 0

Answer: 101.76

Explanation: Remember PE(MD)(AS)? Parentheses go first. You get 9.8. Then multiply 9.8 with 6.2=60.76. Now, subtract 60.76-2, which you get 58.76. Lastly, add 58.76+43=101.76

suter [353]2 years ago
3 0

Answer:

101.76

Step-by-step explanation:

(12.9−3.1)(6.2)−2+43

=(9.8)(6.2)−2+43

=60.76−2+43

=58.76+43

=101.76

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The radius of an orange is 1.5 inches.
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Answer:

14.14

Step-by-step explanation:

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3 years ago
A baby is weighed on a defective scale. He weighed 13 pounds. The baby weighs exactly 10 pounds. What is the percent error?
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30%

Step-by-step explanation:

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3 years ago
Enter the values for the highlighted variables that show how to subtract the rational expressions correctly:
sladkih [1.3K]

The highlighted variables a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

<h3>What is an Expression ?</h3>

An expression is a mathematical statement which consists of variables , constants and mathematical operators.

\rm \dfrac{2}{x^2-36}-\dfrac{1}{x^2+36}\\= \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\=\dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{x(x+6)(x-6)}\\\\=\dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\=\dfrac{g}{x(x-6)}

In the given expression

a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

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8 0
2 years ago
Alice weighs 20 dogs and 20 cats. The mean weight for the dogs is 32kg and the mean weight for cats is 4kg. The range in weight
azamat

With the mean and range, we can estimate the weights of the smallest and largest animals in each group.

For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]

<h3>Which conclusions can be made with the given information?</h3>

We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.

  • From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
  • And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg

(Assuming a normal distribution).

Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:

  • The largest dog weights 32kg + 45kg/2 = 54.5kg
  • The smallest dog weights 32kg - 45kg/2 = 9.5kg

(again, assuming a normal distribution).

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3 0
2 years ago
Hi guys.I just need to know to fix my story.My story was “Before ally started to run her speed was 0mph but then as she ran fast
oksano4ka [1.4K]

Answer:

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