Vertex: (-2,1)
Maximum or Minimum: The graph has minimum point and gives minimum value because the minimum point gives the least y-value. That's why it is called minimum.
End of behavior:
When x approaches positive infinity, f(x) will approach positive infinity.
When x approaches negative infinity, f(x) will approach positive infinity as well.
Why no solution:
The graph doesn't intercept any x-axis. Therefore the graph doesn't have any solutions.
y-intercept: (0,5)
describe shape of the graph:
The graph decreases when x<0 and increases when x>0.
x<0 is concave up but decreasing
x>0 is concave up but increasing
Answer:
"Vx: if x is a valid argument with true premises then x has a true conclusion"
In a symbol form
Vx ( P(x) ⇒ 2(x) )
Step-by-step explanation:
The Following statement in the form ∀x ______, if _______ then _______ is a valid argument and this because any valid argument with "true premises" has a "true conclusion" as well
we will rewrite this statement in a universal condition statement form
assume x is a valid argument with true premises
then the following holds true
p(x) : x is a valid argument with true premises
q(x) : x has true conclusion
applying universal conditional statement
"Vx, if x is a valid argument with true premises then x has a true conclusion"
In a symbol form
Vx ( P(x) ⇒ 2(x) )
Answer:
C. f⁻¹(x) = 3 - 5x
Step-by-step explanation:
To find the inverse of a function, switch x and y and solve for y.
f(x) = (3 - x)/5
Change f(x) to y.
y = (3 - x)/5
Switch x and y.
x = (3 - y)/5
Multiply both sides by 5.
5x = 3 - y
Subtract 3 from both sides.
5x - 3 = -y
Multiply both sides by -1.
-5x + 3 = y
Switch the sides.
y = -5x + 3
Change the equation.
y = 3 - 5x
Answer:
For question 2 the slope is 1. So what you do is get the points you need to put on the graph and move them up one. Like how you did on question 1.
(0.5, 5) (1, 10) (1.5, 15) (2, 20) (2.5, 25)
Question 3 is the same thing but the slope is now 2. Then you would have to pin the points as...
(1, 2) (2, 4) (3, 6) (4, 8) (5, 10)
Hope this helped :)
