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Viktor [21]
3 years ago
15

You have 576 feet of fencing to enclose a rectangular plot of land. Find the dimensions of the rectangular plot that would maxim

ize the area. List the smaller number first.
Mathematics
1 answer:
stiv31 [10]3 years ago
5 0

Answer:

The dimension that maximizes area is 144ft by 144ft

Step-by-step explanation:

Given

P = 576 -- perimeter

Required

The dimension that gives maximum area

Perimeter is calculated as:

P= 2 * (L + W)

So, we have:

2 * (L + W) = 576

Divide through by 2

L + W = 288

Make L the subject

L  = 288 -W

Area is calculated as:

A = L * W

Substitute L  = 288 -W

A = (288 - W) * W

Open bracket

A = 288W - W^2

Differentiate A with respect to W

A' = 288 - 2W

Set to 0 to calculate W

288 - 2W = 0

Collect like terms

2W = 288

Divide by 2

W = 144

Recall that:

L  = 288 -W

L = 288 - 144

L = 144

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Answer:

I would go with the first one.

Step-by-step explanation:

The first one is the only one that increases by the same number. In other words, its slope is constant. A linear function has a constant slope. You can tell that it increases by 1/2 every time.

6 0
3 years ago
4.1 cm the scale on the map is 1 cm=4.5 km. What is the actual distance
evablogger [386]

If you are taking the cm to km then it would be like this

4.5km*4.1cm= 18.45km

5 0
3 years ago
6 is what percent of 8
mars1129 [50]
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3 0
3 years ago
What is the horizontal asymptote of f(x) = (2x+1)/ (x^2-4x+3) +2
evablogger [386]

Answer:

x=3 and x=1

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6 0
3 years ago
What is the image point of (-12, -8) after the transformation R270° 0 D. ?
Gennadij [26K]

Given:

The point is (-12,-8).

Rule of transformation is R_{270^\circ}\circ D_{\dfrac{1}{4}}.

To find:

The coordinates of image after transformation.

Solution:

According to the rule of transformation R_{270^\circ}\circ D_{\dfrac{1}{4}}, first the point is dilated by factor \dfrac{1}{4} with origin as center of dilation after that it was rotated 270 degrees anticlockwise.

If a point is dilated by factor \dfrac{1}{4} with origin as center of dilation, then

(x,y)\to \left(\dfrac{1}{4}x,\dfrac{1}{4}y\right)

(-12,-8)\to \left(\dfrac{1}{4}(-12),\dfrac{1}{4}(-8)\right)

(-12,-8)\to \left(-3,-2\right)

If a point is rotated 270 degrees anticlockwise, then

(x,y)\to (y,-x)

(-3,-2)\to ((-2),-(-3))

(-3,-2)\to (-2,3)

Therefore, the coordinates of image after transformation are (-2,3).

3 0
3 years ago
Read 2 more answers
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