Let s and c be the rate of the boat in still water and the rate of the current, respectively. Then:
108/s-c=3
108/s+c=2
3s-3c=108
2s+2c=108
Solve for s and c
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Answer:
=-4x^2-11x+13
Step-by-step explanation:
Answer:
Step-by-step explanation:
12+x+10=480
22+x=480
x=458
2(12)+2(x+10)=480
24+2x+20=480
44+2x=480
2x=436
x=218
W is the time Woody family used sprinkler.
C is the time Carter family used sprinkler.
Time used total: 50 hours.
W+C = 50 (1)
Total water used is 1900 L.
Woody family used: 40W;
Carter family used 35C.
Equation showing how much water both families used:
40W + 35 C =1900. (2)
We have a system with two equations and two variables. We can use substitution method to solve the system. From equation (1) we express W:
W=50 - C. (1a)
We substitute the variable in equation (2):
40(50 - C) +35C =1900.
We open the parenthesis
2000 -40C +35C =1900,
We combine like terms
2000 -5C =1900,
We subtract 2000 from both sides of the equation
-5C = 1900 - 2000,
We simplify
-5C = -100,
We divide by -5
C = 20.
We substitute the values of C in the equation (1a) and find the value of W:
W = 50 - C,
W = 50 -20 =30.
The Woody family used water for 30 hours and the Carter family used water for 20 hours.
We check our work to be sure we did not make any mistakes:
Total water used:
40 x 30 + 35 x 20 = 1200 + 700 = 1900 L.
43/75
You can divide both the numerator and denominator by five.
Hope this helps. ^^
