Need ko po answer plssssss

15 POINTS. What is the area of the circle segment/shaded area? Picture included please help. Please answer in a way that will fi

PilotLPTM [1.2K]

I hope this helps you

8 0

3 years ago

In the diagram shown, lines m and n are

bonufazy [111]

Answer:

Step-by-step explanation:

If two line 'm' and 'n' are parallel and a transversal line 't' i intersecting these lines at two distinct points,

Sum of interior consecutive angles should be 180°.

(Property of the angles formed between parallel lines and a transversal line)

Therefore, 114° + 64° = 180°

178° = 180°

Which is not true.

Therefore, lines 'm' and 'n' are not the parallel lines.

3 0

3 years ago

Fiona invested $1000 at 7% compounded continuously. At the same time, Maria invested $1100 at 7% compounded daily. How long will

Natali [406]

9514 1404 393

Answer:

14,201 years

Step-by-step explanation:

The two compound interest formulas are ...

A = P·e^(rt) . . . . . continuous compounding at rate r for t years

A = P·(1 +r/365)^(365t) . . . . . daily compounding at rate r for t years

We went the amounts to be equal:

1000·e^(0.07t) = 1100·(1+0.07/365)^(365t)

Dividing by 1000(1 +0.07/365)^(365t), we have ...

((e^0.07)/(1+0.07/365)^365)^t = 1.1

The base of the exponential on the left is ...

( e^0.07)/(1+0.07/365)^365 ≈ 1.00000671149321522

Taking logs, we have ...

t×ln(1.00000671149321522) = ln(1.1)

t = ln(1.1)/ln(1.00000671149321522) ≈ 0.09531018/(6.7114704·10^-6)

t ≈ 14,201.09 . . . . . years

It will take about 14,201 years for the investments to be equal.

_____

<em>Additional comment</em>

The investment value at that time will be about $5.269·10^434. (That's a larger number than <em>anything</em> countable in the known universe, including energy quanta.)

These calculations are beyond the ability of many calculators, so might need to be carefully rewritten if the calculator only keeps 10 significant digits, or only manages exponents less than 100.

This shows that daily compounding is very close in effect to continuous compounding. It would take almost 150 years to make a difference of 0.1% in value.

4 0

3 years ago

Can I have the answers to this? Thanks

Lina20 [59]

A) 13
b) 16
c) 2
d) 13
e) 11

7 0

3 years ago

A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)

Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

$36^6$

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

$5\cdot 36^5$

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

$\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}$

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

$P(A)=P(B)=\dfrac{5}{36}$

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

$axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8$