The answer is m=1.19 hope it helps
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
<h3>
Answer: C) Discriminant</h3>
The formula for the discriminant is
d = b^2 - 4ac
If d < 0, then there are no real number solutions
If d = 0, then you have exactly one real solution
If d > 0, then you have two different real number solutions
97.356
<span>ninety seven and three hundred fifty six <span>thousandths</span></span>
8 1/2=17/2=8.5
24,700 divided by 8.5=2,905,8823
OR
24,700:17/2 =24,700x2/17=2,905,8823