Two significant figures.
The trailing zero is not significant
The region is a segment of a circle with radius √2 lying above the line 
. In polar coordinates, this line has equation
and the circle has equation
The two curves meet when
Then the same integral in polar coordinates is
Solve this like a regular equation:
2n + 5 > 1
2n > -4
n > -2
Hope this helped!
Answer:
6 units
Step-by-step explanation:
I will just assume that you made a typo when typing the question when saying AB is 6√3. Here is the solution if AB = 6√2.
Since it is given that ABC is a right triangle and x labels each of the legs, the triangle is a right isoceles triangle.
Now we can use the right isoceles triangle theorem to solve the problem. This theorem states that if a leg is "x" in a right isoceles triangle, then the hypotenuse is equal to x√2.
Here, the hypotenuse is equal to 6√2. To figure out the legs, you need to solve the equation 6√2 = x√2. It is solved here:
6√2 = x√2 (Divide by √2)
x = 6
The length of the legs are 6 units.
