Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 
Upper limit
X when Z has a pvalue of 0.80. So X when 
Answer:
The rate is 1 ÷ 2 yards per hour
Step-by-step explanation:
The computation of the rate does the amount of yarn changes is given below:
= 3 3 ÷ 4 - 1 1 ÷8
= 15 ÷ 4 - 9 ÷ 8
= 21 ÷ 8 yards
Now divide the above fraction by the number of hours
= 21 ÷ 8 yards ÷ 5 1 ÷ 4
= 21 ÷ 8 × 4 ÷ 21
= 1 ÷ 2 yards per hour
Hence, the rate is 1 ÷ 2 yards per hour
The same would be relevant
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Answer:
6√6 or 14.7
Step-by-step explanation:
Answer:
correct option is △XYZ ~ △X'Y'Z'.
Step-by-step explanation:
since ΔXYZ is dilated by some scale factor so, the resulting triangle can not be congruent to the ΔXYZ. so option 2 is wrong.
as we have explained that the two triangles are not congruent then it's sides and angles also can't be congruent so, option 3 is also incorrect.
As we don't know by what factor the triangle XYZ is dilated so we can't say anything about correctness of option 4 and 5.
ΔXYZ was reflected over a vertical line and then dilated so the resulting ΔX'Y'Z' is similar to ΔXYZ.
i.e., △XYZ ~ △X'Y'Z'.
