6. Find the sum of whole number divisible by 3 and lies between 100 and 200.
2 answers:
Answer:
Step-by-step explanation:
The first number in the sequence = 102
The last number = 198
The number of terms =
L = a1 + (n-1)*d
198 = 102 + (n- 1)*3 Subtract 102
198 - 102 = (n - 1)* 3
96 = (n - 1)*3 divide by 3
32 = n - 1 add 1
33 = n
Sum = (a1 + L ) * n/2
sum = (102+198)*33/2
sum = 300 * 33/2
sum = 150 * 33
sum = 4950
Answer:
4950
Step-by-step explanation:
first find the smallest multiple of 3 thats >100, 3*33=99, so 3*34=102 is the smallest multiple of 3 >100.
next find the greatest multiple of 3 <200, 3*66=198 which is the greatest multiple of 3<200
34-66+1=number of terms=33. then find the average of the terms: 102+198/2=150. 150*33=4950. the answer should be 4950
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