3 years ago

7

Mathematics

1 answer:

elixir [45]3 years ago

4 0

Answer: the answer would be C, 12.

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The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir

zlopas [31]

$\displaystyle\\
\begin{cases}
R_1 = 3R_2\\
\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi 
\end{cases} \\ \\ 
\begin{cases} 
R_1 = 3R_2\\
R_1^2 + R_2^2=12 
\end{cases} \\ \\ 
(3R_2)^2+ R_2^2=12 \\ \\ 
9R_2^2 + R_2^2=12 \\ \\ 
10R_2^2=12\\\\
R_2^2 = \frac{12}{10} = \frac{6}{5} \\ \\ 
R_2 = \boxed{\sqrt{\frac{6}{5}} } \\ \\ 
R_1 = \boxed{3\sqrt{\frac{6}{5}} }$

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3 years ago

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Sliva [168]

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For which value will the equation have only one solution:x=10

iris [78.8K]

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