To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
70% equals to 70/100 in fraction form.
But, you need to write it in simplest form. so, divide both of them from 10 'cause they both can divide completely by it.
70/100 = 7/10
so, your answer is 7/10
Answer:
A. 2(16+12)
Step-by-step explanation:
1. 2x16=32
2. 2x12=24
3. 32+24=56
Answer:
742,380952381 <em>OR</em> 31180/42
Step-by-step explanation:
16/42=0,380952381
742+0,380952381=742,380952381
<em>or</em>
(742*42)/42 + 16/42 = (31164+16) /42 = 31180/42
Answer:
13
Step-by-step explanation:
<h3>13 the answer. that correct or what</h3>
