Name one pair of each type of angles

If f(-7)=7 what is the corresponding order pair solution?

choli [55]

its absoulte value

so the answer is 7

3 0

3 years ago

2 cards are drawn from a standard deck without replacement. What is the probability that at least one of the cards drawn is an a

olya-2409 [2.1K]

Answer:

<h2>The answer is 0.1493.</h2>

Step-by-step explanation:

In a standard deck there are 52 cards in total and there are 4 aces.

Two cards can be drawn from the 52 cards in $^{52}C_2 = \frac{52!}{50!\times2!} = 51\times26$ ways.

There are (52 - 4) = 48 cards rather than the aces.

From these 48 cards 2 cards can be drawn in $^{48}C_2 = \frac{48!}{46!\times2!} = 47\times24$ ways.

The probability of choosing 2 cards without aces is $\frac{47\times24}{51\times26} = \frac{188}{221}$ .

The probability of getting at least one of the cards will be an ace is $1 - \frac{188}{221} = \frac{33}{221} = 0.1493$ .

6 0

3 years ago

‼️help please ASAP ‼️

4vir4ik [10]

By the Law of Sine,
$\frac{ \sin(77) }{89} = \frac{ \sin(46) }{x}$
Solve for x and get x = 65.7.

7 0

3 years ago

A total of 815 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 more stud

kvv77 [185]

Answer:

375 Adult Tickets.

Step-by-step explanation:

Here, we can simply set up an equation using variable x in place of the unknown student/adult tickets.

x = # of adult tickets sold

x + 65 = # of student tickets sold.

1) x + x + 65 = 815 (set both ticket amounts equal to the total)

2) 2x + 65 = 815 (added common variables together)

3) 2x = 750 (negated the +65, subtracted it from both sides)

4) x = 375 (divided both sides by 2)

5) 815 - 375 = 440 (subtracted the x from the total number of adult tickets, to recieve the amount of childrens' tickets.

Therefore,

Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.

5 0

2 years ago

In Rivertown High School, about 30% of the students buy a raffle ticket. Given that a student buys a raffle ticket, there is a 1

lesya [120]

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

Step-by-step explanation:

Step 1 :

Given,

The percentage of students buying the raffle ticket = 30%

The percentage that the student who bought the ticket wins the prize = 10%

We need to determined the probability that randomly selected student will buy a raffle ticket and win a prize.

Step 2 :

The probability that a student buys the raffle ticket = $\frac{30}{100} = \frac{3}{10}$

The probability that a student wins a prize = $\frac{10}{100}$ = $\frac{1}{10}$

The probability that a student who buys the ticket wins a price can be computed by taking the product of the above 2 probabilities.

= $\frac{3}{10}$ × $\frac{1}{10}$ = $\frac{3}{100}$ = 0.03

Step 3 :

Answer :

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

6 0

3 years ago