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2 years ago

Please answer quick!

Mathematics

1 answer:

marysya [2.9K]2 years ago

6 0

Answer:

The correct option is B

(-1)(1/2)(-1)(1)

Step-by-step explanation:

First thing to notice is that there is are two brackets with negative values, which means that the result must also be positive (or have two brackets with negative values).

Looking at the options, we can screen out options A and D, they have three brackets with negative values, and can't be chosen.

It is now between options B and C.

Option B, by inspection is simply 1/2

Option C is 12/4 = 3

The problem itself is 12/35

12/24 = 1/2

12/36 = 1/3

Since 12/35 is about 1/3, it is closer to 1/2 than 3, so 1/2 is the best option.

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PLEASE HELP ASAP I WILL MARK BRILLIANT WHOEVER ANSWERS THANKS (:

Sav [38]

This is geometry, I'm not going to do to them for you because this is homework online and cheating.

You need to find the difference between the two lengths and so some formulas to find the answer.

5 0

3 years ago

Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

4 0

3 years ago

The customers at the bank would like to withdraw money from the automated teller machine. Help them enter their personal ID numb

vlabodo [156]

To withdraw money from the automated teller machine the numeric pattern required to complete the personal ID numbers is 2, 13, 24, 35,46,57,68.

As given in the question,

Using automated teller machine customers at the bank withdraw money

Numeric pattern given for the personal ID numbers is

2, 13, 24, 35

First term 'a'= 2

Common difference between consecutive terms are same

'd'=13 -2

=11

It is an arithmetic progression series

nth term = a+ (n-1)d

5th term = 2 +(5-1)11

=46

6th term =2+(6 -1)11

=57

7th term= 2+ (7-1)11

= 68

Therefore, to withdraw money from the automated teller machine the numeric pattern required to complete the personal ID numbers is 2, 13, 24, 35,46,57,68.

The complete question is:

The customers at the bank would like to withdraw money from the automated teller machine. Help them enter their personal ID numbers by completing the numeric patterns. 2, 13, 24, 35, ___, ___, ____.

Learn more about pattern here

brainly.com/question/14720576

#SPJ1

7 0

1 year ago

Please help me do number 3 and number 4

Marina86 [1]

Hello :
let : A(0,3) B(4,8)
<span>the slope is : (YB - YA)/(XB -XA)
</span>(8-3)/(4-0) = 5/4
same method for 4

3 0

3 years ago

The town of worman grove has collected 28,481 pens for school supplies drive. Their goal is 30,000 pens .Show how to use countin

frosja888 [35]

Answer:

1519

Step-by-step explanation:

if wrong super sooryyyyy :(

5 0

2 years ago