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3 years ago

Please answer quick!

Mathematics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

The correct option is B

(-1)(1/2)(-1)(1)

Step-by-step explanation:

First thing to notice is that there is are two brackets with negative values, which means that the result must also be positive (or have two brackets with negative values).

Looking at the options, we can screen out options A and D, they have three brackets with negative values, and can't be chosen.

It is now between options B and C.

Option B, by inspection is simply 1/2

Option C is 12/4 = 3

The problem itself is 12/35

12/24 = 1/2

12/36 = 1/3

Since 12/35 is about 1/3, it is closer to 1/2 than 3, so 1/2 is the best option.

You might be interested in

Kierston needs to paint a wall of the youth center. She knows that 1 can of paint covers an area of 2.2 square meters. Kierston

Step2247 [10]

Answer:

See Explanation

Step-by-step explanation:

Given

$1\ can = 2.2m^2$

Required

Determine the number of cans for the wall

The dimension of the wall is not given. So, I will use the following assumed values:

$Length=20m$

$Width = 44m$

First, calculate the area of the wall

$Area = Length * Width$

$Area = 20m * 44m$

$Area = 880m^2$

If $1\ can = 2.2m^2$

Then $x = 880m^2$

Cross Multiply:

$x * 2.2m^2 = 1 * 880m^2$

$x * 2.2m^2 = 880m^2$

$x * 2.2 = 880$

Make x the subject

$x = \frac{880}{2.2}$

$x = 400$

400 cans using the assume dimensions.

So, all you need to to is, get the original values and follow the same steps

4 0

3 years ago

Plz help geometry will mark brainliest

stellarik [79]

15+16+10 =41
BH= 41
Bd=15
Df=16
Fh=10

Plz mark me brainalist answer

3 0

3 years ago

HELP PLEASE!!! Thanks!

Irina18 [472]

Answer:

2) $\frac{\sqrt{77}}{11}$

3) 5√2

Step-by-step explanation:

Simplest radical form of an expression is the expression in radical so that there are no more square roots, cube roots, 4th roots, etc left to find, after rationalising the denominator ( if needed ).

2. Here the given expressions,

$\frac{\sqrt{7}}{\sqrt{11}}$