Answer:
![n = 18 \\](https://tex.z-dn.net/?f=n%20%3D%2018%20%5C%5C%20)
Step-by-step explanation:
![\frac{1}{3} n = 6 \\ n = 6 \div \frac{1}{3} \\ n = 6 \times 3 \\ n = 18 \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20n%20%3D%206%20%5C%5C%20n%20%3D%206%20%5Cdiv%20%20%5Cfrac%7B1%7D%7B3%7D%20%20%5C%5C%20n%20%3D%206%20%5Ctimes%203%20%5C%5C%20n%20%3D%2018%20%5C%5C%20)
For A B and C, you just plug in the given number
A
![2(15) + 5 = 35](https://tex.z-dn.net/?f=2%2815%29%20%2B%205%20%3D%2035)
B
![4(20) + 2 = 82](https://tex.z-dn.net/?f=4%2820%29%20%2B%202%20%3D%2082)
C
![6(10) + 5 = 65](https://tex.z-dn.net/?f=6%2810%29%20%2B%205%20%3D%2065)
And for D, you set the equation to 26 and solve for n
![3x + 5 = 26 \\ 3x = 21 \\ x = 7](https://tex.z-dn.net/?f=3x%20%2B%205%20%3D%2026%20%5C%5C%203x%20%3D%2021%20%5C%5C%20x%20%3D%207)
I had to use x instead of n, but for D n=7. :)
The answer is 888+88+8+8+8
Answer:
112.491 = one hundred twelve and four hundred ninety-one
thousandths.
Step-by-step explanation: