Question

Pls help Will mark brainliest :)

Answer 1

Step-by-step explanation:

it is an exponential function but u can solve it by using logarithm so the answer is 2

Answer 2

Answer:

$x=2$

Step-by-step explanation:

$2^{3-2x} =\frac{1}{2}$

taking ln on both the sides.

$3-2x ln2^{} =ln\frac{1}{2}$

$3-2x = \frac{ln(1/2)}{ln(2)}$

$3-2x=-1$

$-2x = -1-3$

$-2x=-4$

$x=-4/-2$

$x=2$

OR

$2^{3-2x} =\frac{1}{2}$

$2^{3-2x} =2^{-1}$ ............... 2 gets cancelled on both sides

${3-2x} ={-1}$

${-2x} ={-1-3}$

$-2x=-4$

$x=-4/-2$

$x=2$