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3 years ago

Please help if possible due in 20 minutes ❤️❤️ f(x) = x2. What is g(x)?

Mathematics

1 answer:

otez555 [7]3 years ago

3 0

Answer:

c. g(x)=(1/2x^2)

Step-by-step explanation:

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Choose an equivalent system of equations to the following system:

andrezito [222]

Answer:

B. 6Fx + 6Gy = 6H

Qx + Ry = S

Step-by-step explanation:

Equivalent equations can be created many ways. One of the simplest is to multiply both sides of the equation by the same number. In the answer above, the first equation has been multiplied by 6. Nothing has been done to the second equation.

_____

<em>Comments on other choices</em>

A: some terms have been multiplied by 6. This changes the equation(s) so they are no longer equivalent to the ones you started with.

B: the correct choice

C: see A.

D: the first equation has been multiplied by 6, so that is equivalent to the original. The second equation has the sign of one of the terms changed, so it is now a different equation.

3 0

3 years ago

Read 2 more answers

I need help on this worksheet for my math hw it’s combing like terms?

maw [93]

What you would do is combine the terms with variables, and combine the terms without.

Answers:
2. -2w-22
3. 15z
4. 7-16s
5. 17w
6. 4-6r
7. 21-8b
8. 8q
9. -18q-9
10. 12q-3

I hope I got all of these right if not that’s embarrassing haha I did all of them in my head I’m pretty sure they’re right

I hope I helped

3 0

3 years ago

en el octagono regular siguiente cuyo lado mide 2 cm. se han trazado arcos de circunferencia de radio 1 en cada uno de los ángul

AnnZ [28]

Answer:

the answer is easy.

Step-by-step explanation:

6 0

3 years ago

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$

6 0

3 years ago

A line thru (5,1) with slope of 3.

VladimirAG [237]

<span>A line thru (5,1) with slope of 3

y - 1 = 3(x - 5)
y = 3x - 15 + 1
y = 3x - 14

hope it helps</span>

7 0

3 years ago