Answer:
What's Yo Question What Chu Need Help With ?
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
14x + 10y = 72
14x + 4y = 96
6y = -24
6 6
y = -4
14x + 10y = 72
14x + 10(-4) = 72
14x - 40 = 72
+ 40 + 40
14x = 112
14 14
x = 8
(x, y) = (8, -4)
If the probability of spinning an A once is 1/12, then the probability of spinning an A 3 times is 3 × 1/12.
3 × 1/12 = 3/36
Simplify
3/36 = 1/12
Answer:
(3,-2)
Step-by-step explanation:
Midpoints bisect a line into two perfectly congruent segments. So, you can find that f was translated down 5=(8-3) and left 1=(5-4). then repeat this step by subtracting x of point e by 1 and the y of point e by 5 to get (3,-2)
