A graphing calculator finds the regression line to be
y = 5.5x + 52
There are 2 options to solve that.
1. The first one is by derivatives.
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)
For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)
Answer:
I think it would be -1 its hard to explain but I am very positive
Step-by-step explanation:
Answer:
y=-log5(x)
Step-by-step explanation:
www!desmos!com/calculator
online graphing calculator. replace the ! for .
Answer:
x = 6
Option A.
Step-by-step explanation:
We know that
If A, B and C are collineal points, they all pass through a common line.
<--------------14-------------->
A-----------B----------------C
<-----x-----><------x+2---->
Based on the problem and the diagram above,
(x) + (x+2) = 14
(2x+2) = 14
(2x) = 12
(x) = 6
