Ask question

Ask question

All categories

3 years ago

14

The circumference of a circle is 75.36 cm. What is the area of the circle?

2 answers:

Anuta_ua [19.1K]3 years ago

7 0

The area of a circle, given the circumference, is found using this formula:

A = C²/4π

Therefore,
A ≈ 451.93 cm²

bekas [8.4K]3 years ago

7 0

451.93 is the short answer.

You might be interested in

Change 0.7 to a common fraction

erma4kov [3.2K]

Answer:

7/10

Step-by-step explanation:

In 0.7 we will change the decimal to fraction. First we will write the decimal without the decimal point as the numerator. Now in the denominator, write 1 followed by one zeros as there are 1 digit in the decimal part of the decimal number. Therefore, we observe that 0.7 (decimal) is converted to 7/10 (fraction).

3 0

2 years ago

MULTIPLE CHOICE QUESTION

Paha777 [63]

Answer:

i think it will be #3

Step-by-step explanation:

3 0

3 years ago

41300 was rounded to the nearest hundred.

KengaRu [80]

Answer:

41,000

Step-by-step explanation:

If it is under 5 you round down. Hope this helps! Plz give brainliest!

5 0

2 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

If a statement is true the its negation is <br><br>A true <br>B false <br>C cannot be determined

aniked [119]

B) False

Because the negation makes it opposite of what is was.

5 0

3 years ago

Read 2 more answers