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zhenek [66]
3 years ago
6

If g(x) =x -7, what if the value of x when g(x) =6

Mathematics
1 answer:
Ronch [10]3 years ago
4 0

Answer:

x=13

Step-by-step explanation:

1. Place 6 in

6=x-7

2. Evaluate

x=6+7

x=13

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What is the answer to <br> 6+0.10x=0.15x+8
asambeis [7]

Let's solve this problem step-by-step.

6+0.1x=0.15x+8

Step 1: Simplify both sides of the equation.

0.1x+6=0.15x+8

Step 2: Subtract 0.15x from both sides.

0.1x+6−0.15x=0.15x+8−0.15x

−0.05x+6=8

Step 3: Subtract 6 from both sides.

−0.05x+6−6=8−6

−0.05x=2

Step 4: Divide both sides by -0.05.

-0.05x/-0.05=2/-0.05

So, the answer for this problem is x=-40

4 0
3 years ago
How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used
MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

• <em>a</em> (1) = 1

• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

and recall the formulas,

\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

So the sum of the first <em>N</em> terms of <em>a</em> (<em>n</em>) is such that

21 × <em>N</em> (<em>N</em> + 1)/2 - 20<em>N</em> = 2332

Solve for <em>N</em> :

21 (<em>N</em> ² + <em>N</em>) - 40<em>N</em> = 4664

21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

4 0
3 years ago
Is it 80% 70% 50% 60%
nexus9112 [7]

Answer:

50%

Step-by-step explanation:

As there are only two sides of the coin it will be 50% each.

7 0
3 years ago
Help hurry !!!!! I need this
Dmitry [639]

Answer:21

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
100y−39,000=55(x−800)
hoa [83]

Answer:

y = 11/20x -50

Step-by-step explanation:

100y−39,000=55(x−800)

Distribute

100y−39,000=55x−44000

Add 39000 to each side

100y−39,000+39000=55x−44000+39000

100y = 55x -5000

Divide each side by 100

100y/100 = 55x/100 - 5000/100

y = 11/20x -50

This is slope intercept form

where 11/20 is the slope and -50 is the y intercept

4 0
3 years ago
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