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Alex
2 years ago
5

What the hell is 5+5

Mathematics
1 answer:
Maru [420]2 years ago
5 0

Answer:

72

Step-by-step explanation:

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Find the area of each sector. Use exact answers
BigorU [14]

Answer:

B) 54π in²

Step-by-step explanation:

area of full circle = πr² = 81π in²

area of 4π/3 segment = (81)(4π/3)/2π = 54π in²

6 0
3 years ago
What is the width of a rectangle with length 14cm and area 161 cm^2
Inessa05 [86]

Answer:

Step-by-step explanation:

The area of a rectangle can be found with the formula A = l*w, where l is the length of the rectangle and w is the width.

From the given problem statement, we know that l = 14 and A = 161, so we can fill in those values in the formula anbd solve for w to get the width:

A = l*w

161 = 14w

Divide both sides by 14 to isolate w by itself:

\frac{161}{14} = \frac{14w}{14}

w = 11.5

3 0
2 years ago
Read 2 more answers
Slope is 2 and (3,4) is on the line. solve
pogonyaev

Answer:

Step-by-step explanation:

y-y1 = m(x-x1)

y-4 = 2(x-3)

y-4=2x-6

y= 2x -6+4

y=2x-2

8 0
2 years ago
An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let
Advocard [28]

Answer:

P(t)=3,000,000-3,000,000e^{0.0138t}

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

P'(t)=K(3,000,000-P(t))

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

P'(t)+KP(t)= 3,000,000K

The <em>integrating factor </em>is

e^{Kt}

Multiplying both sides of the equation by the integrating factor

e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K

Hence

(e^{Kt}P(t))'=3,000,000Ke^{Kt}

Integrating both sides

e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C

e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C

P(t)=3,000,000+Ce^{-Kt}

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138

And the equation that models the number of people (in millions) who become aware of the product by time t is

P(t)=3,000,000-3,000,000e^{0.0138t}

5 0
3 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
2 years ago
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