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dusya [7]
2 years ago
11

A 6 ounce package of fruit snacks contains 45 pieces how many pieceswould would you expect in a10 ounce package

Mathematics
1 answer:
pochemuha2 years ago
8 0

Answer:

75 pieces

Step-by-step explanation:

1. determine how many pieces per ounce by dividing 45 by 6 (# of pieces in a 6 oz bag)

    45/6= 7.5 pieces per ounce

2. multiply 7.5 (for one ounce) by 10

    7.5*10 = 75

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Jenna has $50 to spend at a local craft fair. The entrance price for the fair is $10. At a pottery stand. Jenna finds cups that
taurus [48]

Answer:

8

Step-by-step explanation:

4.5x+10<=50

4.5x<=50-10

4.5x<=40

x<=8.9

round down because can't go beyond 50

x=8 max

8 0
3 years ago
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Steve built a square dog pen that has a perimeter of 240 inches.
Trava [24]
Perimeter of square = 4 x l

so ATC 4 x l = 240
= 240/40= l
so 60 = l

the answer is 60 inches.
6 0
3 years ago
Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
Yanka [14]

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

3 0
2 years ago
Joan adopt two kittens snowflake has a mass of 2 kg and midnight has a mass of 997 g what is the difference between the masses o
exis [7]

Answer:

Given,

mass of snow flake = 2 kg

mass of midnight = 997 gm

Now,

1 kg = 1000 gm

2 kg = 1000 * 2

= 2000 gm

therefore the difference between the masses of the kittens = 2000

- 997

= 1003 gm (is the answer)

7 0
3 years ago
In​ 2012, the population of a city was 5.69 million. The exponential growth rate was 2.87​% per year. ​a) Find the exponential g
Angelina_Jolie [31]

Answer:

a) The exponential growth function

P(t) = 5,690,000(1.0287)^t

b) 6,742,868.7374 million

c) 12.04 years

d) 2439.0243902

Step-by-step explanation:

In​ 2012, the population of a city was 5.69 million. The exponential growth rate was 2.87​% per year. ​

The formula for exponential growth is given as:

P(t) = Po( 1 + r) ^t

Where P = Population size after time t

Po = Initial population size

r = Growth rate in percentage

t= time in years

a) Find the exponential growth function.

P(t) = Population size after time t

Po = Initial population size = 5.69 million

r = Growth rate in percentage = 2.87% = 0.0287

t= time in years

The Exponential growth function

P(t) = 5,690,000(1 + 0.0287)^t

P(t) = 5,690,000(1.0287)^t

​b) Estimate the population of the city in 2018. ​

From 2012 to 2018 = 6 years

t = 6 years

Hence,

P(t) = Po( 1 + r) ^t

P(t) = 5,690,000(1 + 0.0287)^6

P(t) = 5,690,000(1.0287)^6

P(t) = 6,742,868.7374 million

c) When will the population of the city be ​8 million?

P(t) = 8,000,000

P(t) = Po( 1 + r) ^t

P(t) = 5,690,000(1 + 0.0287)^t

8,000,000 = 5,690,000(1 + 0.0287)^t

8,000,000 = 5,690,000(1.0287)^t

Divide both sides by 5,690,000

8,000,00/5,690,000 = 5,690,000(1.0287)^t/5,690,000

= 1.4059753954 = 1.0287^t

Take logarithm of both sides

log 1.4059753954 = log 1.0287^t

Log 1.4059753954 =t Log 1.0287

t = Log 1.4059753954/Log 1.0287

t = 12.041740264

t = 12.04 years

​d) Find the doubling time.

The formula is given as 70/Growth rate

= 70/0.0287

= 2439.0243902

4 0
2 years ago
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