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GarryVolchara [31]
3 years ago
10

HELP ME!! I NEED SERIOUS HELP RN!

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

hii, ok so (3, 2)

Step-by-step explanation:

Just imagine the dot at (3, -4). Now just go up 6 units.  **i added a picture, its kinda junky, sorry**

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Please someone explain how to solve this piecewise function!!!! Im super confused
Xelga [282]

Answer:

From top to bottom:

0, 1, 2, -8, -8

Step-by-step explanation:

We are given the piecewise function:

g(x) = \left\{        \begin{array}{ll}            0.5x+1 & \text{if } x \leq 2 \\            -8 & \text{if } x > 2        \end{array}    \right.

Row 1:

We want to find g(-2).

Since -2 is less than (or equal to) 2, we will use the first equation. Thus:

g(-2)=0.5(-2)+1=-1+1=0

Row 2:

Likewise, 0 is less than or equal to 2. We will continue to use the first equation:

g(0)=0.5(0)+1=1

Row 3:

2 is not less than 2 but it is equal to 2. So we will continue to use the first equation:

g(2)=0.5(2)+1=1+1=2

Row 4 and 5:

Both 4 and 6 are greater than 2. Thus, we will use the second equation. Therefore:

g(4)=-8\text{ and } g(6)=-8

7 0
3 years ago
X+50=278<br><br> PLease help really quick
Anon25 [30]

Answer: x= 228

x= 278-50

x=228

7 0
3 years ago
Read 2 more answers
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
I really need math help.
fenix001 [56]

When you see the 'line' is increasing starting from 0 to 2 hours, this indicates that the person on the graph is riding up a hill. This is known as positive acceleration or constant positive acceleration.

Where you see the 'line' stays the same 2 to 5 hours, this can indicate that the bike rider is doing one or two things. One thing the biker could be doing is taking a rest, and the other could be that the biker is riding at a leveled ground. This could be known as having constant velocity or zero acceleration.

Finally, where the 'line' is decreasing from 5 to 6 hours, this can indicate that biker is riding, possibly, down a hill. This is known as negative acceleration.

And of course, when the 'line' is going up again from 6 to 7 hours, this indicates that the biker is riding up a hill or increasing his speed. This is known as positive acceleration or constant positive acceleration.

•

•

- Marlon Nunez

4 0
3 years ago
What is the slope of (8,5) and (-9,5)
3241004551 [841]
(8,5)
(-9,5)
=
0/17
Answer is Zero
3 0
4 years ago
Read 2 more answers
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